a(n+1)-an=2而a2=a1+2 所以a2=4 a3=6所以为等差数列 an=2nsn=n×n+ns10=110
已知数列{an}满足a1=2,an=a(n+1)-2,求an及S10
1个回答
相关问题
-
已知数列{an}满足:a1=3,an=Sn-1+2n,求数列an及sn
-
已知数列{an}满足a1=2 an=aN-1——1(n>=2)求an?
-
已知数列an满足a1=2,an=a(n-1)+2n,(n≥2),求an
-
已知数列{an}满足a1=1.a2=2,(a(n+1)+an)/an=(a(n+2)-an+1)/an+1 n∈N* 求
-
已知数列an满足a1=1/2,an+1=an+1/n²+n,求an
-
已知数列{an}满足a1=1/2,a(n+1)=an+1/n^2+n,求an.
-
已知数列an满足a1=1,An+1=an+2的n次幂,求a10
-
已知数列an满足an-a(n-1)=1/(√﹙n+1﹚+√n) (n≥2) 求an
-
已知数列an满足a(n+1)=an+3n+2,且a1=2,求an
-
已知数列{an}满足a1=33,an+1-an=2n 则求an/n?