(1)(a²+4b²)²-16a²b²
=(a²+4b²)²-(4ab)²
=(a²-4ab+4b²)(a²+4ab+4b²)
=(a-2b)²(a+2b)²
(2)x²-2xy+y²-1
=(x-y)²-1
=(x-y-1)(x-y+1)
在实数范围内分解因式:(1)(a²+4b²)²-16a²b²;(2)x
(1)(a²+4b²)²-16a²b²
=(a²+4b²)²-(4ab)²
=(a²-4ab+4b²)(a²+4ab+4b²)
=(a-2b)²(a+2b)²
(2)x²-2xy+y²-1
=(x-y)²-1
=(x-y-1)(x-y+1)