Question

5.4g铝箔在足量的氧气中燃烧时,消耗氧气多少克,这些氧气在标准状况下占多少升,产

Answer 1

4Al+3O2==点燃==2Al2O3

108 3 204

5.4g n m

108/5.4g = 3/n = 204/m

n = 0.15mol,m = 10.2g

所以消耗O2质量 = 32*0.15 = 4.8g,体积 = 22.4*0.15 = 3.36L

生成Al2O3质量 = 10.2g