3条式左边加起来除以9.得x+y+z=0
2x+5y+4z=6,3x+y-7z=-4,4x+3y+12z=-2 求x+y+z
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相关问题
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2x+5y+4z=6,3x+y-7z=-4,x+y-z=?
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若2x+5y+4z=6,3x+y-7z=—4,求x+y-z
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若2x+5y+4z=6,3x+y-7z=—4,求x+y+z
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（1）y=2x-7 6x+3y+2z=2 3x-4z=4 (2) 4x+9y=12 3y-2z=1 7x+5z=19/4
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y=2x-7 3y+2z=2 3x-4z=4和4x+9y=12 3y-2z=1 7x+5z=19/4
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已知2x+5y+4z=6 3x+y-7z=-4求x+y-z
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2x-y=7 x+y+z=25x+3y+z=2 x-2y+z=-1 3x-4z=4 x+2y+3z=-1x+y-z=6x
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2X+2Y+Z=4 X+4Y+3Z=6 X+3Y+2Z=7
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3x-y+z=4,2x+3y-z=12,x+y+z=6
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{3x-y+z=4,2x+3y-z=12,x+y+z=6