原式= lim (sin1/n + sin2/n+...+sin100/n)/(1/n)
=lim (sin1/n)/(1/n) + lim (sin (2/n))/(1/n) + ... lim sin(100/n)/(1/n)
=lim (1/n)/(1/n) + lim (2/n)/(1/n)+...+ lim (100/n)/(1/n)
=1+2+...+100
=5050
limn(sin1/n+sin2/n+...+sin100/n)求极限过程
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