Question

方程4(3-2x)+3a+2=7-4a-3(x-5)的解不比2a+1小,求a的取值范围

Answer 1

4(3-2x)+3a+2=7-4a-3(x-5)

12-8x+3a+2=7-4a-3x+15

x=(-8+7a)/5

不小于2a+1

x≥2a+1

(-8+7a)/5≥2a+1

-8+7a≥10a+5

3a≤-13

a≤-13/3