Sn-Sn-3=an+an-1+an-2=3*an-1=51 an-1=17
Sn=(a1+an)*n/2=(a2+an-1)*n/2=(3+17)*n/2=100
n=10
用余弦定理
cosADB=(AD^2+BD^2-AB^2)/2AD*BD
cosADC=-cosADB=(AD^2+CD^2-AC^2)/2AD*CD
CD=BD
BD=根6
Sn-Sn-3=an+an-1+an-2=3*an-1=51 an-1=17
Sn=(a1+an)*n/2=(a2+an-1)*n/2=(3+17)*n/2=100
n=10
用余弦定理
cosADB=(AD^2+BD^2-AB^2)/2AD*BD
cosADC=-cosADB=(AD^2+CD^2-AC^2)/2AD*CD
CD=BD
BD=根6