1/n(n+2)=[1/n-1/(n+2)]/2
1/1*3+1/2*4+1/3*5+...+1/18*20
=[(1-1/3)+(1/2-1/4)+(1/3-1/5)+...+(1/18-1/20)]/2
=[1+1/2-1/19-1/20]/2
=531/760
如果不懂,请Hi我,祝学习愉快!
1/n(n+2)=[1/n-1/(n+2)]/2
1/1*3+1/2*4+1/3*5+...+1/18*20
=[(1-1/3)+(1/2-1/4)+(1/3-1/5)+...+(1/18-1/20)]/2
=[1+1/2-1/19-1/20]/2
=531/760
如果不懂,请Hi我,祝学习愉快!