Question

已知函数f(x)=sin^4-2根号3sinxcosx-cos^4x+1

Answer 1

f(x)=sin^4x-2根号3sinxcosx-cos^4x+1

=(sin^2x-cos^2x)(cos^2x+sin^2x)-2根号3sinxcosx+1

=-cos2x-根号3sin2x+1

= -2sin(2x+π/6)+1

当0