x²-x²y+xy²-x+y-y²
=(x²-y²)-(x²y-xy²)-(x-y)
=(x-y)(x+y)-xy(x-y)-(x-y)
=(x-y)(x+y-xy-1)
=-(x-y)(xy-x-y+1)
=-(x-y)[(xy-x)-(y-1)]
=-(x-y)[x(y-1)-(y-1)]
=-(x-y)(x-1)(y-1)
x²-x²y+xy²-x+y-y²,让我看得懂
1个回答
相关问题
-
（x+y）(x²-xy+y²)+3xy=x²-xy+y²+3xy 这个怎么变得?
-
(x+y)(x²-xy+y²),(x-y)(x²+xy+y²)
-
方程组{2005x-2007y=2003:；2004x-2006y=2002} 麻烦过程清楚些 能让我看懂 谢谢
-
计算：｛x√x+x√y / xy-y²}-{x+√xy+y / x√x-y√y}
-
作乘法:(x+y)(x²-xy+y²),(x-y)(x²+xy+xy+y²).(
-
(x-y)²(x+y)²(x²-xy+y²)²(x²+xy+
-
x²-y²/xy - xy-y²/x(y-x)
-
谁帮我化简：[(x+y)(x-y)-(x+y)^2-2y(x-y)-2xy]÷xy
-
x√x+x√y)/(xy-y2)-(x+√xy+y)/(x√x-y√y)化简
-
（x√x+x√y)÷(xy-y^2)--(x+√xy+y)÷(x√x-y√y)