f(x)=2cosxsin(x+π)-根号3/2

f(x)=2cosxsin(x+π)-根号3/2 求这个函数的最小正周期

1个回答

f(x)=2cosxsin(x+π)-sqrt(3/2)
=-2cosxsinx-sqrt(3/2)
=-sin2x-sqrt(3/2)
最小正周期= 2π/2= π