求数列的极限:lim(2^n)/[1+2^(n+1)]
1个回答
n->正无穷时,1/2^n -> 0.
2^n/[1+2^(n+1)] = 1/[2+1/2^n] -> 1/[2+0] = 1/2
lim_{n->正无穷}2^n/[1+2^(n+1)] = 1/2
相关问题
数列的极限:lim(1-1/n)^(-2n+3) n->无穷
求下列数列的极限:lim(1+(1/2)+……+(1/2^n))/(1+(1/3)+……+(1/3^n))
求数列的极限:lim(n-∞).(1-1/n)的n次方
lim(3n^2-2n+6)/(5n^2+7n+9)求数列的极限
求极限lim1/n2(√n+√2n+…√n2﹚
求下列数列的极限:lim(n→∞) [1/(2*5)+1/(5*8)+1/(8*11)+……+1/(3n-1)*(3n+
高数 极限运算法则lim(1+2+……+n)/n^2=lim1/n^2+lim2/n^2+……+limn/n^2=0n→
求极限lim(√(n^2-1) -n)/(n-√(n^2+1))的值
求极限lim [1/(n+1)+1/(n+2)+...+1/(n+n)] (n→∞)
求极限 lim n[ e^2- (1+1/n)^2n] n->无穷