Question

一个直角三角形的三边分别是m²+1,2m,m²-1,则此三角形是什么?

Answer 1

[m^2+1]^2 = m^4 + 2m^2 +1

[m^2-1]^2 = m^4 - 2m^2 +1

(2m)^2 = 4m^2

这就是许多直角三角形但不是全部而已,其中m^2+1为斜边,另外两个为直角边

m m^2+1 m^2-1 2m

2 5 3 4

3 8 10 6

4 17 15 8

............

GOOD LUCK~