延长AB到E,使BE=BD,连接DE,
则∠E=∠BDE,∠ABC=∠BDE+∠E=2∠E,
∵∠ABC=2∠C;∴∠C=∠E,
∵∠DC=∠DAE,AD=AD,
∴ΔADE≌ΔADC,
∴AC=AE,
即AC=AB+BD.