Question

（根号2-根号3-根号6）×（根号3-根号2-根号6）

Answer 1

(√2-√3-√6)×(√3-√2-√6)

=[-√6+(√2-√3)]×[-√6-(√2-√3)]

=(-√6)^2-(√2-√3)^2

=6-(2-2√6+3) = 1+2√6