解一个二次函数的解,(51/10)x^2-(119/10)x+17/5

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  • (51/10)x^2-(119/10)x+17/5

    =(51/10)[x^2-(119/10)(10/51)x+(17/5)(10/51)]

    =(51/10)[x^2-119x/51+34/51]

    =(51/10)[x^2-119x/51+(119/102)²-14161/10404+6936/10404]

    =(51/10)[(x-119/102)²-7225/10404]

    =(51/10)[(x-119/102)²-(85/102)²]

    =(51/10)(x-119/102-85/102)(x-119/102+85/102)

    =(51/10)(x-204/102)(x-34/102)

    =(51/10)(x-2)(x-1/3)

    =(x-2)(51x/10-17/10)