Question

已知log12 27=a,求log6 16

Answer 1

a=log12(27)

=3log12(3)

=3/log3(12)

=3/[2log3(2)+1]

∴log3(2)=(3-a)/2a

log6(16)=log3(16)/log3(6)=4log3(2)/[log3(2)+1]=4(3-a)(3+a)