原式=a(a+b)(a-5b)/a(a-b))(a-5b)=(a+b)/(a-b)
a/(a-b)=2,即a=2b,代入后得3.
x/(1+x)+y/(1+y)+z/(1+z)=1/((1/x)+1)+1/((1/y)+1)+1/((1/z)+1)
=1/((a+b)/c+1)+1/((b+c)/a+1)+1/((c+a)/b+1)
=(a+b+c)/(a+b+c)=1
原式=a(a+b)(a-5b)/a(a-b))(a-5b)=(a+b)/(a-b)
a/(a-b)=2,即a=2b,代入后得3.
x/(1+x)+y/(1+y)+z/(1+z)=1/((1/x)+1)+1/((1/y)+1)+1/((1/z)+1)
=1/((a+b)/c+1)+1/((b+c)/a+1)+1/((c+a)/b+1)
=(a+b+c)/(a+b+c)=1