解；
f(x) = （5ex^3 + 2π x^2 + 3√2 x + 7）/ log4(16) + log6(36) + log9(81)
=（5ex^3 + 2π x^2 + 3√2 x + 7）/ (2+2+2)
=1/6（5ex^3 + 2π x^2 + 3√2 x + 7）
f'(x)=1/6(15ex^2+4πx+3√2）
f‘(2)=1/6(60e+8π+3√2)
=10e+4/3π+√2/2
求导：f(x) = （5ex^3 + 2π x^2 + 3√2 x + 7）/ log4(16) + log6(36)
1个回答
相关问题
-
log5(1/3) x log36 x log6a=2,求a
-
已知x满足不等式2(log2^x)^2-7log2^x+3≤0,求f(x)=log2^(x/2) X log2^(x/4
-
1.3log2(x+4)-4log2(3-x)-5log2(x-2) 2.4In(x^2-16)-8[In(x+4)-2
-
已知x满足不等式2(log1/2x)^2+7log1/2x+3≤0.求函数f(x)=(log2x/4)(log2x/2)
-
已知x满足不等式2[log2(x)]^2-7[log2(x)]+3≤0,求函数f（x）=[log2(x/2)]*[log
-
2 log(3x)= log 4 +log(6-x)怎么求...急
-
求x的值 log4^x=-2/3 log2^(log5^x)=0
-
解方程3log(x)4+2log(4x)4+3log(16x)4=0
-
Log0.5x(x(2))-14log16x(x(3))+40log4x(1x )=0
-
求值：3^(log3 (25) )+(-C(5,4)^(log2 1)+16^(log4(2sin(π/2))=