设a^(loga b)=x,式子两边取底数为a的对数 ,
即loga(a^(loga b))=loga x
loga b=loga x
得x=b
所以
-(2^(-log2 1/3)-1)
=-(2^(-log2 3^-1)-1)
=-(2^(log2 3)-1)
=-(3-1)
=-2
f(log2 1/3)=-(2^(-log2 1/3)-1)=-2 怎么算
2个回答
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