Question

因为(1+tanθ)/(1-tanθ)=3+2根号2,所以tanθ=根号2/2 所以是怎么出来的

Answer 1

(1+tanθ)/(1-tanθ)=3+2√21+tanθ=(3+2√2)(1-tanθ)1+tanθ=3+2√2-(3+2√2)tanθ(4+2√2)tanθ=2+2√2tanθ=(2+2√2)/(4+2√2)=(1+√2)/(2+√2)=[(1+√2)(2-√2)]/[(2+√2)(2-√2)]=√2/2