(5a³-2a²-6a+6)-(3a³-3a²-8a+3)+(-2a³-a²-2a+2)
=5a³-2a²-6a+6-3a³+3a²+8a-3-2a³-a²-2a+2
=5a³-3a³-2a³-2a²+3a²-a²-6a+8a-2a+6-3+2
=(5a³-3a³-2a³)+(-2a²+3a²-a²)+(-6a+8a-2a)+6-3+2
=0+0+0+5
=5
因为代数式的值是常数,与a的值无关,
所以小华不小心将已知条件抄成a=501,其答案仍然是对的
(5a³-2a²-6a+6)-(3a³-3a²-8a+3)+(-2a³-a²-2a+2)
=5a³-2a²-6a+6-3a³+3a²+8a-3-2a³-a²-2a+2
=5a³-3a³-2a³-2a²+3a²-a²-6a+8a-2a+6-3+2
=(5a³-3a³-2a³)+(-2a²+3a²-a²)+(-6a+8a-2a)+6-3+2
=0+0+0+5
=5
因为代数式的值是常数,与a的值无关,
所以小华不小心将已知条件抄成a=501,其答案仍然是对的