f(x)=(sin4x+cos4x+sin2xcos2x)/(2-2sinxcosx)=[(sin2x+cos2x)^2-2sin2xcos2x+sin2xcos2x]/(2-2sinxcosx)=(1+sinxcosx)/2
高中三角函数化简问题求化简函数f(x)=(sin4x+cos4x+sin2xcos2x)/(2-2sinxcosx)si
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