Question

x²-x-2＝0求（x²-x）²-1+根号3分之x²-x+2被根号3的值

Answer 1

x²-x-2=0

x²-x=2

(x²-x)²-(x²-x+2√3)/(1+√3)

=2²-(2+2√3)/(1+√3)

=4-2

=2