sinx=1/3,sin(x+y)=1,求sin(2x+y)
1个回答
cosx=±√[1-(sinx)^2]=±2√2/3
cos(x+y)=0
sin(2x+y)=sin[x+(x+y)]
=sinxcos(x+y)+cosxsin(x+y)
=±2√2/3
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