2=log2(4) 0=log2 1
log0.5 (5-x)=log2[1/(5-x)]
∴log2(4)+log2[1/(5-x)]+log2(1/x)>0
∴log2[4/x(5-x)]>log2(1
)
∴4/x(5-x)>1
又∵5-x>0 1/x>0
∴0
解不等式'要具体过程
2=log2(4) 0=log2 1
log0.5 (5-x)=log2[1/(5-x)]
∴log2(4)+log2[1/(5-x)]+log2(1/x)>0
∴log2[4/x(5-x)]>log2(1
)
∴4/x(5-x)>1
又∵5-x>0 1/x>0
∴0