Question

已知3的x次方等于4,3的y次方等于6,求9的2x-y次方加27的x-y次方的值

Answer 1

9^(2x-y)+27^(x-y)=3^(4x-2y)+3^(3x-3y)=(3^x)^4/(3^y)^2+(3^x)3/(3^y)3=4^3/6^2+4^3/6^3=64/36+64/108=256/108=64/27