f(1/2014)=m*log3(1/2014)+n*log5(1/2014)+2=10,
即-(m*log3(2014)+n*log5(2014))+2=10
所以m*log3(2014)+n*log5(2014) = -8
f(2014)=m*log3(2014)+n*log5(2014)+2=-8+2=-6
f(1/2014)=m*log3(1/2014)+n*log5(1/2014)+2=10,
即-(m*log3(2014)+n*log5(2014))+2=10
所以m*log3(2014)+n*log5(2014) = -8
f(2014)=m*log3(2014)+n*log5(2014)+2=-8+2=-6