对代数式(a-b)^2与a^2-2ab+b^2当a,b分别取下列值时,求这两个代数式的值并猜想出结论.
（1）a=7,b=3
(a-b)^2=(7-3)^2=16
a^2-2ab+b^2=7^2-2*7*3+3^2=49-42+9=16
(2)a=-5,b=4
(a-b)^2=(-5-4)^2=81
a^2-2ab+b^2=(-5)^2-2*(-5)*4+4^2=25+40+16=81
(3)a=-8,b=-2
(a-b)^2=[-8-(-2)]^2=(-6)^2=36
a^2-2ab+b^2=(-8)^2-2(-8)(-2)+(-2)^2=64-32+4=36
结论(a-b)^2=a^2-2ab+b^2
求135.7^2-2*135.7*35.7+35.7^2的值
135.7^2-2*135.7*35.7+35.7^2=(135.7-35.7)^2=100^2=10000