2X1 - X2 +X3-X4=0
X2+3X3-6X4=0
2X1-X2-3X4=0
2X1-2X2-2X3+5X4=0的矩阵化为 2 -1 1 -1 0
0 1 3 -6 0
0 0 -1 -2 0
0 0 0 0 0
所以方程组为2x1-x2+x3-x4=0
x2+3x3-x4=0
-x3-x4=0
解得:X4=K(K为任意常数)
X3=-K
X2=4K
X1=3K
2X1 - X2 +X3-X4=0
X2+3X3-6X4=0
2X1-X2-3X4=0
2X1-2X2-2X3+5X4=0的矩阵化为 2 -1 1 -1 0
0 1 3 -6 0
0 0 -1 -2 0
0 0 0 0 0
所以方程组为2x1-x2+x3-x4=0
x2+3x3-x4=0
-x3-x4=0
解得:X4=K(K为任意常数)
X3=-K
X2=4K
X1=3K