sin(2x+π4)+cos(2x+π4)
=√2[sin(2x+π4)*√22+cos(2x+π4)*√22]
=√2[sin(2x+π4)cosπ4+cos(2x+π4)sinπ4]
=√2sin[(2x+π4)+π4]
这里把(2x+π4)看做整体
函数f(x)=sin(2x+π\4)+cos(2x+π\4)=根号2sin(2x+π/2) 老师 这题还是不能理解,带入
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