Question

编写程序求e的近似值.e=1+1/1!+1/2!+1/3!+.+1/n!

Answer 1

#include

int main()

{

x09int a = 1, b = 1;

x09float e = 0;

x09do

x09{

x09x09a *= b;

x09x09e += 1 / a;

x09x09++b;

x09} while (1 / a >= 1e-4);

x09printf("e=%fn", e);

x09return 0;

}