Question

[x(x^2 y^2-xy)-y(x^2-x^3y)]÷3x^2y

Answer 1

[x(x^2 y^2-xy)-y(x^2-x^3y)]÷3x^2y

=(x^3y^2-x^2y-x^2y+x^3y^2)÷3x^2y

=(2x^3y^2-2x^2y)÷3x^2y

=2x^3y^2÷3x^2y-2x^2y÷3x^2y

=2xy/3-2/3