Question

(x-3)分之x-(x^2-3x)分之(x+6)+x分之1等于几?

Answer 1

(x-3)分之x-(x^2-3x)分之(x+6)+x分之1等于几?

=x²/x(x-3)-(x+6)/x(x-3)+(x-3)/x(x-3)

=(x²-x-6+x-3)/x(x-3)

=(x²-9)/x(x-3)

=(x+3)/x

[x+1-(1-x)分之1]除以[x-(x-1)分之x^2]等于几?

=[(x+1)+1/(x-1)] ×(x-1)/(-x)

=x²/(x-1) ×(x-1)/(-x)

=-x