Question

求多项式的求导f(x)=x(x-1)(x-2)(x-3)(x-4)…………（x-1000)求f（x）的导数式,重赏.【要

Answer 1

当成两个因式的乘积那样求导 具体方法如下

f'(x)=(x-1)(x-2)(x-3)(x-4)…………（x-1000)

+x(x-2)(x-3)(x-4)…………（x-1000)

+x(x-1)(x-3)(x-4)…………（x-1000)

+...+x(x-1)(x-2)(x-3)…………（x-999)

=x(x-1)(x-2)(x-3)(x-4)……（x-1000)[1/x+1/(x-1)+1/(x-2)+...+1/(x-1000)]