f(a)= 2 tana-[2(sina/2)^2 - 知识问答

f(a)= 2 tana-[2(sina/2)^2-1]/[(sina/2)(cosa/2)],求f(π/12)

1个回答

f(a)= 2 tana-[2(sina/2)^2-1]/[(sina/2)(cosa/2)]
=2tana+cosa/(1/2sina)
=2(tana+cota)
=2(sina/cosa+cosa/sina)
=2(sin^2a+cos^2a)/(sinacosa)
=4/sin(2a)
f(π/12)=4/sin(π/6)=8

相关问题