3x²y+xy²-[2xy²-4x²y+(x²y-2xy²)
1个回答
原式=3x²y+xy²-2xy²+4x²y-x²y+2xy²
=3x²y+4²y-x²y+xy²-2xy²+2xy²
=6x²y+xy²
=xy(6x+y)
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