大一无机及分析化学,关于标准平衡常数计算.

2个回答

  • 2SO2 (g) + O2 (g) = 2SO3 (g)

    1、求298K时的△rGmθ

    △rHmθ = 2△fHmθ (SO3,g) - 2△fHmθ (SO2,g) - △fHmθ (O2,g)

    = - 395.7*2 - (-296.83)*2 - 0

    = -197.74 (kJ/mol)

    △rSmθ = 2 Smθ (SO3,g) - 2 Smθ (SO2,g) - S mθ (O2,g)

    = 2*256.6 - 2*248.1 - 205.03

    = -188.03 (J / mol K)

    △rGmθ = △rHmθ - T △rSmθ

    = -197.74 + 298 * 188.03*10^-3

    = -141.7 (kJ/mol)

    2、求298K时的 Kθ

    △rGmθ = - RT ln Kθ

    -141.7 *1000 = - 8.314 * 298 ln Kθ

    ln Kθ = 57

    3、求1000K时的Kθ

    ln (K1θ / K2θ ) = (△rHmθ / R )(1/ T2 - 1/T1)

    式中,T2 = 1000K,T1 = 298K,代入上式求出K2θ