4xy-4x²-y²/2x-y÷(4x²-y²)
1个回答
=-(4x²-4xy+y²)/(2x-y)×1/(2x+y)(2x-y)
=-(2x-y)²/(2x-y)×1/(2x+y)(2x-y)
=-1/(2x+y)
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