原式=(x-y)(x²+2xy+y²-xy)-(x-y)(x²-2xy+y²+xy)
=(x-y)(x²+xy+y²)-(x+y)(x²-xy+y²)
=(x³-y³)-(x³+y³)
=-2y³
结果和x无关
所以不蹲x取何值,结果都不变