当n=k时,左端=(k+1)(k+2)(k+3)…(2k),
当n=k+1时,左端=(k+2)(k+3)…(2k)(2k+1)(2k+2),
故当“n从k到k+1”左端需增乘的代数式为
(2k+1)(2k+2)
(k+1) =2(2k+1),故选 B.
当n=k时,左端=(k+1)(k+2)(k+3)…(2k),
当n=k+1时,左端=(k+2)(k+3)…(2k)(2k+1)(2k+2),
故当“n从k到k+1”左端需增乘的代数式为
(2k+1)(2k+2)
(k+1) =2(2k+1),故选 B.