因式分解:(1)(x+3)^2-(3x+9)

3个回答

  • (1)(x+3)^2-(3x+9)

    =(x+3)^2-3(x+3)

    =(x+3)(x+3-3)

    =x(x+3)

    (2) x(6m-nx)-nx^2

    =x[(6m-nx)-nx]

    =x(6m-2nx)

    (3) 2-5(3x-2)^2+3x

    =2-45x²+60x-20+3x

    =-45x²+63x-18

    =-9(5x²-7x+2)

    =-9(5x-2)(x-1)

    (4) x(b+c-d)-y(d-b-c)-b-c+d

    =x(b+c-d)+y(b+c-d)-(b+c-d)

    =(x+y-1)(b+c-d)

    (5) (4a-5b)(3m-2p)+(4b-a)(3m-2p)

    =(3m-2p)(4a-5b+4b-a)

    =(3m-2p)(3a-b)

    (6) ab(x-2y)-ac(2y-x)+ab(2x-4y)

    =ab(x-2y)+ac(x-2y)+2ab(x-2y)

    =a(x-2y)(b+c-2b)

    =a(x-2y)(c-b)

    (7) (a-b)^2(a+b)^3-(b-a)^2(b+a)^2

    原式=(a-b)²(a+b)³-(a-b)²(a+b)²

    =(a-b)²(a+b)²(a+b-1)