Question

-3(a^2bc)^2*1/2a(bc)^3-（abc）^3*(-abc)^2

Answer 1

-3(a^2bc)^2*1/2a(bc)^3-（abc）^3*(-abc)^2

=-3a^4b^2c^2*1/2ab^3c^3-（abc）^3*(abc)^2

=-3/2*a^5b^5c^5-(abc)^5

=-3/2*(abc)^5-(abc)^5

=-5/2(abc)^5