Question

求函数y=sin（2x-π/6）√2在「0,π/6」上的最大值是?

Answer 1

y=sin（2x-π/6）√2

0 ≤ x ≤π/6

0 ≤ 2x ≤π/3

-π/6 ≤ 2x-π/6 ≤π/6

在 -π/6 ≤ 2x-π/6 ≤π/6 范围内函数单调增

2x-π/6 = π/6 时,ymax=sinπ/6 *根号2 = 1/2 *根号2 = 根号2 /2