求极限Lim(x→0)1/xsinx-1/xtanx
2个回答
原极限=1/xtanx(1/cosx-1)
=1/xtanx·(1-cosx)/cosx
1/x^2·0.5x^2/cosx
=0.5
相关问题
求极限:lim(x趋于0)(1/(xtanx)-1/x^2)
求极限lim x→0 (1/xsinx+xsin1/x)
lim(x→0)[(1/x^2)-(1/xsinx)] 求极限,
求极限:lim(x→0)(sinx)^2/[√(1+xsinx)-√(cosx)]
求lim(x→0)(1-con2x)/xSinx的极限,
求极限~lim(x→0)[(1+xsinx)^1/2-cosx]/sin^2(x/2)
lim(x→0)(1-cos2x)/(xsinx)的极限
lim (tanx-sinx)/x (x→0)的极限; lim (1-cos4x)/xsinx (x→0)的极限
求极限的一道题 lim(x趋于0) (xsin 1/x-1/xsinx)=
lim(x→0)[(1/x^2)-(1/xtanx)]