m（x-y)²-x+y
=m(x-y)²-(x-y)
=(x-y)(mx-my-1)
5(y-x)²+3（x-y)
=5(x-y)²+3(x-y)
=(x-y)(5x-5y+3)
15*（a-b)²-3y(b-a)
=15(a-b)²+3y(a-b)
=3(a-b)(5a-5b+y)
6(m-n)³-12（n-m)²
=6(m-n)³-12(m-n)²
=6(m-n)²(m-n-2)
13/(x-4)-10/(x-3)=1/(x-1)
去分母,两边同时乘以(x-4)(x-3)(x-1)得：
13（x-3)(x-1)-10(x-4)(x-1)=(x-3)(x-4)
13(x²-4x+3)-10(x²-5x+4)=x²-7x+12
整理：2x²+5x-13=0
解得x1=(-5-√129)/4,x2=(-5+√129)/4
x1,x2均是原方程的根