(根号2+2根号3-3根号6)*(根号2-2根号3+3根号6)
2个回答
原式=[√2+(2√3-3√6)][√2-(2√3-3√6)]
=(√2)²-(2√3-3√6)²
=2-(12-12√18+54)
=2-12+36√2-54
=-64+36√2
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