Question

解方程:2(X+根号下X的平方-1)=(X-1+根号下X+1)的平方

Answer 1

2[x+√(x²-1)]=[x-1+√(x+1)]²

2[x+√(x+1)(x-1)]=(x-1)²+2(x-1)√(x+1)+(x+1)

2x+2+√(x+1)(x-1)=x²-2x+1+x+1+2(x-1)√(x+1)

2x=x²-x+2

x²-3x+2=0

(x-2)(x-1)=0

x=2

x=1