一道物理计算题为节能减排,建筑上普遍采用空心砖替代实心砖.如图所示,质量3.6kg的某空心砖,规格为20cm×15cm×

1个回答

  • 1、20cm=0.2m,10cm=0.1m,15cm=0.15m

    V=0.2*0.1*0.15*60%=9/5000m^3

    ρ=m/V=3.6kg/9/5000m^3=2kg/m^3

    2、3.6/ 60%*(1-60%)=2.4kg

    3、三种情况:

    (1)F=3.6kg*9.8N/kg=35.28N

    S=0.2m*0.1m*60%=0.012m^2

    P=F/S=35.28N/0.012M^2=2940Pa

    (2)F=3.6kg*9.8N/kg=35.28N

    S=0.2m*0.15m*60%=0.018m^2

    P=35.28N/0.018m^2=1960Pa

    (3)F=3.6kg*9.8N/kg=35.28N

    S=0.15m^2*0.1m^2*60%=0.009m^2

    P=F/S=35.28N/0.009m^2=3920Pa

    希望有用