①3x+2y+z=x+y+z+2x+y=10+2x+y=14,即2x+y=4,y=4-2x.
②由2x+3y-z=1得：3y=1+z-2x=3(4-2x).整理后得：z=11-4x.
③把①和②中的y和z代入原式,得：x=1,y=2,z=7.
④代入原式验算：3×1+2×2+7=14,验算正确.
3x+2y+z=14 { x+y+z=10 2x+3y-z=1
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